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+--- Thread: QID: AN437 and AN491 (/thread-2111.html)
QID: AN437 and AN491 - slawekstec - 09-27-2022
QID AN437
posted answer : ipv6 address fc00:0000:aaaa:a15d:1234:2343:8aca/64
Why correct answer has only 28 hex-digits, not 32 hex-digits ? I do not see :: in this answer
QID AN491
IMO correct answer should be : ip domain-name domain ...since the question asks for command BEFORE entering the command to generate RSA key
RE: QID: AN437 and AN491 - forumsupport - 10-04-2022
Thank you for your feedback. Both questions have been fixed.
RE: QID: AN437 and AN491 - ejohnson7 - 10-07-2022
when was the test last updated on H2P site ?
RE: QID: AN437 and AN491 - forumsupport - 10-10-2022
(10-07-2022, 12:10 AM)ejohnson7 Wrote: when was the test last updated on H2P site ?
Last Updated: October 04, 2022
https://www.how2pass.com/ccna-200-301-practice-test-questions.php
RE: QID: AND49 - darrenglorioso - 11-15-2022
Can someone please help understand the answers to this question?
172.16.2.128=>255.255.255.128
172.16.3.64 =>255.255.255.224
172.16.3.128=>255.255.255.240
172.16.3.192=>255.255.255.248
172.16.4.0 =>255.255.254.0
Am I making this too hard for myself? I just don't get it.
Please advise
Thanks
dglorioso
RE: QID: AND49 - slawekstec - 11-15-2022
(11-15-2022, 06:01 PM)darrenglorioso Wrote: 172.16.2.128=>255.255.255.128 = block of 128 IP's (126+2)
172.16.3.64 =>255.255.255.224 = block of 32 IP's (30+2)
172.16.3.128=>255.255.255.240 = block of 16 IP's (14+2)
172.16.3.192=>255.255.255.248 = block of 8 IP's (6+2)
172.16.4.0 =>255.255.254.0 = block of 512 IP's (510+2)
+2 in each block represent ==> NetworkID and BroadcastID
I do not see a copy of the question but I assume that you
have to assign a block of IP's to fulfil specific request.
Google search: IP CALCULATOR that will provide additional info about each block/subnet
RE: QID: AN437 and AN491 - serbet - 12-20-2022
AN 437:
In explanation you posted the same answer as correct and as incorrect.
RE: QID: AN437 and AN491 - forumsupport - 12-21-2022
Thank you for your feedback. We have fixed the answer and explanation.