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The networks connected to router R2 have been summarized as a 192.168.176.0/21 route and
sent to R1. Which two packet destination addresses will R1 forward to R2? (Choose two.)
A. 192.168.194.160
B. 192.168.183.41
C. 192.168.159.2
D. 192.168.183.255
E. 192.168.179.4
F. 192.168.184.45
Answer: B, E
Why answer B,E correct? why other options are incorrect?

A /21 is a 248 submask. 248 is a block size of 8. "256-248=8 This is the RP-5c method that Wendel Odom teaches."
Count up in 8's. 8-16-24....160-168-176-184. So you range of summarized routes are between 176-184.
What Ip address are in that range? 183.41 and 179.4, D is a Broadcast address so its wrong.

The Ethernet networks connected to router R1 in the graphic have been summarized for router
R2 as 192.1.144.0/20. Which of the following packet destination addresses will R2 forward to R1,
according to this summary? (Choose two.)
A. 192.1.159.2
B. 192.1.160.11
C. 192.1.138.41
D. 192.1.151.254
E. 192.1.143.145
F. 192.1.1.144
Answer: A, D
Why answer A,D correct? why other options are incorrect?

A /20 is a submask of 240 which has a Block size of 16. "256-240=16 This is the RP-5c method that Wendel Odom teaches."
Count by 16's. 16,32,48...128,144,160. So the range that is summarized is between 144 and 160
159 and 151 fall inbetween that range right?
Makes A and D correct.

palash010

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