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question on ip address
#2
I have been practice testing this type of subnetting today, so here goes:

    The network portion of the address is the first 23 bits as indicated by the subnet mask 255.255.254.0 or in binary 11111111.11111111.11111110.00000000.

the first address 113.10.4.0  we know 113.10 is a network portion of address by 255.255

so the 3rd octet needs to be analyzed since 3rd octet of mask is 254 as follows

                                          binary
                            113.10.  00000100.    0
                            113.10.  0000010 | 0.00000000
                                                      ^
                                                this is the boundary btwn network and host.
                                                to the right you see all zeros so this is a network address with no
                                                host specified and can therefore not be assigned to a host.

the second address    186.54.3.0  analyze 3rd octet

                              186.54.  00000011.    0
                              186.54.  0000001 | 1.00000000
                                                      ^
                                                  boundary -  so  the 1.00000000 to the right is a valid host of the
                                                                    186.54.2.0  network
                              186.54.3.0  is therefore a valid host address


the third address        175.33.3.255  analyze 3rd octet

                              175.33.  00000011.  11111111
                              175.33.  0000001 | 1.11111111
                                                        ^
                                                  boundary  -  here you see all ones to the right (host portion) which
                                                                    is broadcast address for network 175.33.2.0 and       
                                                                    therefore 175.33.3.255 is NOT a valid host address.


the fourth address        26.35.2.255    analyze 3rd octet

                                26.35.  0000001 | 0.11111111
                                                        ^
                                                              here 0.11111111 is a valid host address for network
                                                              26.35.2.0

the fifth address            17.35.36.0    check 3rd

                                  17.35.    0010010 | 0.00000000
                                                          ^
                                                              here all zeros to the right = 17.35.36.0  255.255.254.0 is a
                                                                                                    network with no host specified
                                                                                                    Not a valid host address




                                    I hope this helps ------  study on!
                                 
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Messages In This Thread
question on ip address - by kelvinwgr - 10-28-2010, 07:43 AM
Re: question on ip address - by bpman57 - 10-28-2010, 07:00 PM
Re: question on ip address - by kelvinwgr - 10-29-2010, 01:58 AM
Re: question on ip address - by bpman57 - 10-29-2010, 05:33 PM
Re: question on ip address - by kelvinwgr - 10-31-2010, 03:30 AM
Re: question on ip address - by bpman57 - 11-08-2010, 02:44 PM
Re: question on ip address - by kelvinwgr - 11-10-2010, 02:55 PM
Re: question on ip address - by fanren - 06-17-2011, 08:51 AM
Re: question on ip address - by megathumpzilla - 09-24-2011, 09:11 PM
Re: question on ip address - by chas - 01-28-2012, 01:17 AM

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